You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
Example 1:
Input: 2 Output: 2 Explanation: There are two ways to climb to the top. 1. 1 step + 1 step 2. 2 steps
Example 2:
Input: 3 Output: 3 Explanation: There are three ways to climb to the top. 1. 1 step + 1 step + 1 step 2. 1 step + 2 steps 3. 2 steps + 1 step
Java Solution :
class Solution {
public int climbStairs(int n) {
if(n == 0 || n == 1 || n == 2)
return n;
int previousstep = 2;
int prepreviousstep = 1;
for(int i = 3; i <= n ; i++){
int current = previousstep + prepreviousstep;
prepreviousstep = previousstep;
previousstep = current;
}
return previousstep;
}
}
Time Complexity : O(n)
Space Complexity : O(1)
Approach : Dynamic Programming Tabularization.
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