Given a linked list, determine if it has a cycle in it.
To represent a cycle in the given linked list, we use an integer
pos
which represents the position (0-indexed) in the linked list where tail connects to. If pos
is -1
, then there is no cycle in the linked list.
Example 1:
Input: head = [3,2,0,-4], pos = 1 Output: true Explanation: There is a cycle in the linked list, where tail connects to the second node.
Example 2:
Input: head = [1,2], pos = 0 Output: true Explanation: There is a cycle in the linked list, where tail connects to the first node.
Example 3:
Input: head = [1], pos = -1 Output: false Explanation: There is no cycle in the linked list.
Java Solution : O(n) space and O(n) time complexity
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
Set<ListNode> nodeSeen = new HashSet<>();
while(head !=null){
if(nodeSeen.contains(head))
return true;
else
nodeSeen.add(head);
head=head.next;
}
return false;
}
}
Java Solution : O(n) Time Complexity O(1) Space Complexity
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
ListNode fast = head;
ListNode slow = head;
while(fast!=null&&fast.next!=null){
slow = slow.next;
fast = fast.next.next;
if(slow==fast)
return true;
}
return false;
}
}
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