Find N Unique Integers Sum up to Zero
Given an integer n
, return any array containing n
unique integers such that they add up to 0
.
Example 1:
Input: n = 5 Output: [-7,-1,1,3,4] Explanation: These arrays also are accepted [-5,-1,1,2,3] , [-3,-1,2,-2,4].
Example 2:
Input: n = 3 Output: [-1,0,1]
Example 3:
Input: n = 1 Output: [0]
Constraints:
1 <= n <= 1000
class Solution {
public int[] sumZero(int n) {
if(n == 0){
return new int[] {0};
}
int value = n;
int [] uniqueIntegers = new int[n];
for(int i=0,j=n-1;i<j;i++,j--){
uniqueIntegers[i]= value;
uniqueIntegers[j] = value * -1;
value--;
}
return uniqueIntegers;
}
}
TC : O(N) SC: O(N)
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