Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.
Note:
- Your returned answers (both index1 and index2) are not zero-based.
- You may assume that each input would have exactly one solution and you may not use the same element twice.
Example:
Input: numbers = [2,7,11,15], target = 9 Output: [1,2] Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.
Java Solution :
class Solution {
public int[] twoSum(int[] numbers, int target) {
HashMap<Integer,Integer> map = new HashMap<Integer,Integer>();
for(int i=0; i < numbers.length ; i++){
if(map.containsKey(target-numbers[i]) && i!=map.get(target-numbers[i])){
return new int [] {map.get(target-numbers[i])+1,i+1};
}else{
map.put(numbers[i],i);
}
}
return null;
}
}
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