Given an array of integers, find if the array contains any duplicates.
Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.
Example 1:
Input: [1,2,3,1] Output: true
Example 2:
Input: [1,2,3,4] Output: false
Example 3:
Input: [1,1,1,3,3,4,3,2,4,2] Output: true
class Solution:
def containsDuplicate(self, nums: List[int]) -> bool:
uniqueset = set()
for num in nums:
if num in uniqueset:
return True
else:
uniqueset.add(num)
return False
Time Complexity : O(n)
Space Complexity : O(n)
class Solution:
def containsDuplicate(self, nums: List[int]) -> bool:
nums.sort()
for i in range(0,len(nums)-1):
if nums[i] == nums[i+1]:
return True
return False
Time Complexity : O(nlogn)
Space Complexity : O(1)
No comments:
Post a Comment