Given an array with n objects colored red, white or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library's sort function for this problem.
Example:
Input: [2,0,2,1,1,0] Output: [0,0,1,1,2,2]
Follow up:
- A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. - Could you come up with a one-pass algorithm using only constant space?
class Solution:
def sortColors(self,nums: List[int]) -> None:
"""
Dutch National Flag Problem
"""
# For all idx nums[idx < p0] == 0 and idx < p0
# For all idx idx > p2 : nums[idx > p2] == 2
# curr is pointing current element
if not nums:
return
curr = p0 = 0
p2 = len(nums) -1
while curr <= p2:
if nums[curr] == 0:
nums[p0],nums[curr] = nums[curr],nums[p0]
curr = curr+1
p0 += 1
elif nums[curr] == 2:
nums[curr],nums[p2] = nums[p2],nums[curr]
p2 -= 1
else:
curr+=1
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